If 2x+3y−6=0 and 9x+6y−18=0 cuts the axes in concyclic points, then the centre of the circle, is

The equation of the circle passing through the points of intersection of the lines 2x+3y−6=0 and 9x+6y−18=0 with the coordinate axes is(2x+3y−6)(9x+6y−18)−(2×6+9×3)xy=0⇒x2+y2−5x−5y+6=0The coordinates of the centre are (5/2,5/2).