First slide
Introduction to Determinants
Question

 If x, y, z are different from zero and Δ=ab-yc-za-xbc-za-xb-yc=0 then the value of the expression  ax+by+cz is 

Moderate
Solution

Applying , R¯2R¯2-R¯1,R¯3R¯3-R¯1 we get 

Δ=ab-yc-z-xy0-x0z=0

Expanding along C3, we get

(c-z)-xy-x0+zab-y-xy=0

  (c-z)(xy)+z(ay+bx-xy)=0

  cxy-xyz+ayz+bxz-xyz=0

  ayz+bzx+cxy=2xyz

  ax+by+cz=2

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