First slide
Introduction to Determinants
Question

If x, y, z are different from zero and Δ=abyczaxbczaxbyc=0, then the value of the expression ax+by+cz is

Moderate
Solution

Applying R2R2R1,R3R3R1, we get

Δ=abyczxy0x0z=0

Expanding along C3 we get

(cz)-xy-x0+zabyxy=0

or (c - z) (xy) + z(ay + bx - xy) = 0

or cxy - xyz + ayz + bxz - xyz = 0

or ayz + bzx + cxy = 2xyz

or ax+by+cz=2

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