If x,y,z,are in GP and ax=by=cz, then
logac=logba
logba=logcb
logcb=logac
None of these
Given, x, y, z are in GP and ax=by=cz Since, x, y, z are in GP.
⇒ y2=xz ......(i)
we have
ax=by=cz=k (say); k>0
On taking log both sides, we get
xloga=ylogb=zlogc=logk⇒ x=logkloga,y=logklogb,z=logklogc
On substituting the values of x,y and z in Eq. (i), we get
logklogb2=logkloga⋅logklogc
⇒ (logk)2(logb)2=(logk)2loga⋅logc⇒ (logb)2=loga⋅logc⇒ logalogb=logblogc
∴ logba=logcb ∵logexlogey=logyx