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If x−41=y−21=z−k2 lies in the plane 2x - 4y + z = 7 then the value of k is

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answer is 7.

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Detailed Solution

As the line x−41=y−21=z−k2 lies in the plane 2x - 4y + z=7 , the point (4,2,k) through which it passes must also lie on the given plane, and hence 2×4-4×2+k=7 or k=7

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If x−41=y−21=z−k2 lies in the plane 2x - 4y + z = 7 then the value of k is