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If $x^{2} + y^{2} + z^{2} = r^{2},$ then $\tan^{- 1} (\frac{x y}{z r}) + \tan^{- 1} (\frac{y z}{x r}) + \tan^{- 1} (\frac{x z}{y r}) =$

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Correct option is B

We have, tan−1⁡xyzr+tan−1⁡yzxr+tan−1⁡xzyr=tan−1⁡ xyzr+yzxr+xzyr−xyzr31−x2+y2+z2r2=tan−1⁡∞=π2

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If x2+y2+z2=r2, then tan−1⁡xyzr+tan−1⁡yzxr+tan−1⁡xzyr=

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Ready to Test Your Skills?

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If $x^{2} + y^{2} + z^{2} = r^{2},$ then $\tan^{- 1} (\frac{x y}{z r}) + \tan^{- 1} (\frac{y z}{x r}) + \tan^{- 1} (\frac{x z}{y r}) =$