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Questions  

If x+y+z=xyz, then tan1x+tan1y+tan1z=

a
0
b
π/2
c
1
d
none of these

detailed solution

Correct option is A

We have,          tan−1⁡x+tan−1⁡y+tan−1⁡z=  tan−1⁡x+y+z−xyz1−(xy+yz+zx)=tan−1⁡0=0

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