If the x-intercept of the line y=mx+2 is greater than 1 /2, then the gradient of the line lies in the interval

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(−1,0)

−14,0

−∞,−4

−4,0

answer is D.

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Detailed Solution

Given equation of line is y=mx+2⇒x−2m+y2=1it is given that x-intercept of the above line is greater than 12∴−2m−12>0⇒−2m−12>0⇒−4+m2m>0⇒4+m2m<0⇒−4

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