Q.
If the x-intercept of the line y = mx + 2 is greater than 12, then the gradient of the line lies in the interval
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a
(−1,0)
b
−14,0
c
(−∞,−4)
d
(−4,0)
answer is D.
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Detailed Solution
Given equation of line is y = mx + 2 ⇒ x−2m+y2=1It is given that x-intercept of the above line is greater than l/2.∴ −2m>12⇒ −2m−12>0⇒ 4+m2m<0⇒ −4
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