If the x-intercept of the line y = mx + 2 is greater than 12, then the gradient of the line lies in the interval
(−1,0)
−14,0
(−∞,−4)
(−4,0)
Given equation of line is y = mx + 2
⇒ x−2m+y2=1
It is given that x-intercept of the above line is greater than l/2.∴ −2m>12⇒ −2m−12>0⇒ 4+m2m<0⇒ −4<m<0