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If $y + C o s θ = S i n θ$ has a real solution then

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−2≤y≤2

y>2

y≤−2

y≤1

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detailed solution

Correct option is A

y=sinθ−cosθ it has solution if |c|≤a2+b2⇒−2≤y≤2

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If y+Cosθ=Sinθ has a real solution then

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If $y + C o s θ = S i n θ$ has a real solution then