If y=cos x+sin x, then dydx at x=2π3 is

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1-32

123-1

none of these

answer is C.

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Detailed Solution

In neighborhood of x=2π3, cosx=-cos x and sin x=sin xor y=-cosx+sinx∴ dydx=sin x+cos xThus, at x=2π3, we get dydx=sin2π3+cos2π3=3-12.

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