If 2y=Cot−1⁡3cos⁡x+sin⁡xcos⁡x−3sin⁡x2x∈0,π2 then dydx is equal to

cot−1⁡32cos⁡x+12sin⁡x12cos⁡x−32sin⁡x=cot−1⁡sin⁡x+π3cos⁡x+π3=cot−1⁡tan⁡x+π3=π2−tan−1⁡tan⁡x+π3π2−x+π3=π6−x               0