Questions
a
y'0+y''0=1
b
y''0=2
c
y'0+y''0=3
d
y''0=0
detailed solution
Correct option is B
The given equation is y2+logecos2x=y,x∈-π2,π2Differentiate both sides with respect tox2yy'-2tanx=y'...............(1)2yy''+2y'2-2sec2x=y''................(2) when x=0 y2+loge 1=yy2-y=0, ⇒y=0,1 if x=0 and y=0⇒y'(0)=0∣ if x=0 and y=1⇒y'(0)=0 equation (2)2yy''+2y'2-2sec2x=y'' at x=0⇒2yy''-2=y''⇒y''(2y-1)=2⇒y''(0)=22y-1=-2;y=02y=1 ⇒y''(0)=2Talk to our academic expert!
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If the slope of the tangent to the curve is maximum at x = 1 and curve has minim value 1 at x = 0, then the curve which also satisfies the equation is
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