If y = sin mx, then the value of the determinant yy1y2y3y4 y5y6y7 y8, where yn=dnydxn is
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a
m9
b
m2
c
m3
d
0
answer is D.
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Detailed Solution
We have y = sin mx, therefore y1 = m cos mx, y2 = -m2 sin mx, etc.∴ Δ=yy1y2y3y4y5y6y7y8=sinmxmcosmx−m2sinmx−m3cosmxm4sinmxm5cosmx−m6sinmx−m7cosmxm8sinmx=m12sinmxcosmx−sinmx−cosmxsinmxcosmx−sinmx−cosmxsinmx=0