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Questions  

If y=sin3θsinθ,θnπ then

a
y∈[−1,3]
b
y∈(−∞,−1]
c
y∈(3,∞)
d
y∈[−1,3)

detailed solution

Correct option is D

We have,y=sin⁡3θsin⁡θ⇒y=3−4sin2⁡θ⇒sin2⁡θ=3−y4Now,0

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