If y=sin7sin−1x then 1−x2y2−xy1=
−49y
−7y
49y
7y
y=sin7sin−1x⇒1−x2⋅y2−2x21−x2y1=−7sin7sin−1x⋅71−x2⇒1−x2y2−xy1=−7y(7)⇒1−x2y2−xy1=−49y.