First slide

Derivatives

Question

$If y = \frac{\sqrt{1 - \sin^{- 1} x}}{1 + \sin^{- 1} x} then y^{'} (0) =$

Moderate

A

0
B

1
C

-1
D

2

Solution

$y' = \frac{1}{2} \frac{\sqrt{1 + \sin^{- 1} x}}{1 - \sin^{- 1} x} \frac{(1 + \sin^{- 1} x) (- \frac{1}{\sqrt{1 - x^{2}}}) - (1 - \sin^{- 1} x) \frac{1}{\sqrt{1 - x}}}{{(1 - \sin^{- 1} x)}^{2}}$
$y' (0) = \frac{1}{2} \frac{\sqrt{1 + 0}}{1 - 0} \frac{(1 + 0 \cdot (- \frac{1}{1}) - (1 - 0) \frac{1}{1})}{{(1 + 0)}^{2}} = \frac{1}{2} (- 2) = - 1$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App