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Q.

If y=1−sin−1⁡x1+sin−1⁡x then y′(0)=

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a

0

b

1

c

-1

d

2

answer is C.

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Detailed Solution

y'=121+sin−1x1−sin−1x(1+sin−1x)(−11−x2)−(1−sin−1x)11−x(1−sin−1x)2y'(0)=121+01−01+0⋅−11−1−0111+02=12−2=−1
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