If y=tan−1⁡log⁡ex2log⁡ex2+tan−1⁡3+2log⁡x1−6log⁡x then dydxx−2+dydxx−3=

y=tan−1⁡1−2log⁡x1+2log⁡x+tan−1⁡3+2log⁡x1−6log⁡x=tan−1⁡1−2log⁡x1+2log⁡x+3+2log⁡x1−6log⁡x1−1−2log⁡x1+2log⁡x3+2log⁡x1−6log⁡x=tan−1⁡(−2)⇒dydx=0⇒dydxx=2+dydxx=3=0