If y=tan−1(secx+tanx) then dydx=
1
12
-1
0
y=tan−1(secx+tanx)=tan−11cosx+sinxcosx=tan−1cosx2+sinx22cos2x2−sin2x2=tan−1cosx2+sinx2cosx2−sinx2 =tan−11+tanx21−tanx2=tan−1tanπ4+x2=π4+x2 Hence, y=π4+x2 Differentiate both sides dydx=12