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If $y = (1 + \tan A) (1 - \tan B)$ where $A - B = \frac{π}{4}$ ,then $(y + 1)^{y + 1}$ is equal to

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Correct option is C

A−B=π4 or tan⁡(A−B)=tan⁡π4or tan⁡A−tan⁡B1+tan⁡Atan⁡B=1or tan⁡A−tan⁡B−tan⁡Atan⁡B=1or tan⁡A−tan⁡B−tan⁡Atan⁡B+1=2or (1+tan⁡A)(1−tan⁡B)=2⇒y=2Hence, (y+1)y+1=(2+1)2+1=(3)3=27

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If y=(1+tan⁡A)(1−tan⁡B) where A−B=π4,then (y+1)y+1 is equal to

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If $y = (1 + \tan A) (1 - \tan B)$ where $A - B = \frac{π}{4}$ ,then $(y + 1)^{y + 1}$ is equal to