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Q.

If y=tan-12x1+22x+1, then dydx at x=0 is :

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a

-35log2

b

25log2

c

-32log2

d

None

answer is A.

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Detailed Solution

y=tan−12x(2−1)1+2x⋅2x+1=tan−12x+1−2x1+2x⋅2x+1=tan−12x+1−tan−12x⇒dydx=2x+1log21+22(x+1)−2xlog21+22x∴dydxx=0=(log2)25−1=log2−35
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