First slide
Derivatives
Question

If  y=x(logx)log(logx),then  dydxis

Moderate
Solution

y=x(logx)log(logx)

logy=(logx)(logx)log(logx)(1)

Taking log of both sides, we get 

log(logy)=log(logx)+log(logx)log(logx)

Diff. w.r.t x, we get 

1logy.1ydydx=1xlogx+2log(logx)logx1x

=2log(logx)+1xlogx

dydx=yx.logylogx(2log(logx)+1)

Substituting the value of log y from (1), we get 

yx(logx)log(logx)(2log(logx)+1)

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