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Q.

If y=2xlog⁡x then dydx at x=e is

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a

0

b

log2

c

e

d

e2

answer is A.

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Detailed Solution

logy=xlogxlog21ydydx=log⁡2log⁡x−x1x(log⁡x)2dydx=log⁡2⋅y⋅(log⁡x−1)(log⁡x)2=log⁡2⋅2e⋅(1−1)(log⁡e)2=0
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