If y=∫x2x3 1logtdt (where x>0 ), then find dydx
x(x−1)(logx)−1
(x−1)(logx)−1
x(x−1)(logx)
x(logx)−1
y=∫x2x3 1logtdt∴ dydx=ddxx31logx3−ddxx21logx2=3x23logx−2x2logx=x(x−1)(logx)−1