First slide
Derivatives
Question

 If y=axax..... then the value of dydx is 

Moderate
Solution

 y=ax axax.....y=axylogy=xylogalog(logy)=ylogx+log(loga)

Diff   w.r. to ‘x’

1logy1ydydx=yx+logxdydx+odydx1ylogylogx=yxdydx1ylogylogxylogy=yxdydx=y2logyx[1ylogylogx]

 

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