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Q.

If y=ax2x−ax−bx−c+bxx−bx−c+cx−c+1 then y'y=

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a

1xaa−x+bb−x+cc−x

b

aa−x+bb−x+cc−x

c

1xax−a+bx−b+cx−c

d

ax−a+bx−b+cx−c

answer is A.

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Detailed Solution

y=ax2x−ax−bx−c+bxx−bx−c+c+x−cx−c=ax2x−ax−bx−c+bxx−bx−c+xx−c=ax2x−ax−bx−c+xx−cbx−b+1=ax2x−ax−bx−c+xx−cb+x−bx−b=ax2x−ax−bx−c+x2x−bx−c=ax2+x2x−ax−ax−bx−c=x3x−ax−bx−c∴log y=3logx−logx−a−logx−b−logx−cDifferentiating w.r.t. x,⇒1ydydx=3x−1x−a−1x−b−1x−c⇒y'y=3x−1x−a+1x−b+1x−c=1x−1x−a+1x−1x−b+1x−1x−c=−1xax−a+bx−b+cx−c=1xaa−x+bb−x+cc−x
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