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If $(1 - y) (1 + 2 x + 4 x^{2} + 8 x^{3} + 16 x^{4} + 32 x^{5}) = 1 - y^{6}$ , $(y \neq 1),$ then a value of $\frac{y}{x}$ is

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detailed solution

Correct option is B

We can rewrite the given expression as(1−y)1−(2x)61−2x=1−y6one of the possible values of y is clearly 2x. Therefore, one of the possible values of y/x is 2.

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If(1−y)1+2x+4x2+8x3+16x4+32x5=1−y6, (y≠1), then a value of yx is

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If $(1 - y) (1 + 2 x + 4 x^{2} + 8 x^{3} + 16 x^{4} + 32 x^{5}) = 1 - y^{6}$ , $(y \neq 1),$ then a value of $\frac{y}{x}$ is