If(1−y)1+2x+4x2+8x3+16x4+32x5=1−y6, (y≠1), then a value of yx is
12
2
14
4
We can rewrite the given expression as
(1−y)1−(2x)61−2x=1−y6
one of the possible values of y is clearly 2x. Therefore, one of the possible values of y/x is 2.