If y=y(x) and it follows the relation 4xexy=y+5sin2x, then y1(0) is
If x=0→y=0 4xexy=y+5sin2x,diff. w. r. t. x4exy+4xexyxdydx+y=dydx+10sinxcosxput x=04e0+0=y'(0) +0y1(0)=4