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$If y = y (x) and \frac{2 + \sin x}{y + 1} \frac{dy}{dx} = - \cos x, y (0) = 1 then y (π / 2) is$

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Correct option is A

dyy+1=−cos⁡x2+sin⁡xdx⇒ln⁡(y+1)=−log⁡(2+sin⁡x)+log⁡c⇒y+1=c2+sin⁡x, put x=0,y=1→c=4y(π2)+1=42+sinπ2=43⇒y(π2)=13

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If y=y(x) and 2+sin⁡xy+1dydx=−cos⁡x,y(0)=1 then y(π/2) is

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$If y = y (x) and \frac{2 + \sin x}{y + 1} \frac{dy}{dx} = - \cos x, y (0) = 1 then y (π / 2) is$