If yz−x2zx−y2xy−z2xz−y2xy−z2yz−x2xy−z2yz−x2zx−y2=r2u2u2u2r2u2u2u2r2, then
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a
r2=x+y+z
b
r2=x2+y2+z2
c
u2=yz+zx+xy
d
u2=xyz
answer is B.
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Detailed Solution
In the left-hand determinant, each element is the cofactor of the elements of the determinantx y zy z xz x y=Δ∗( say )Hence,Δ∗2=xyzyzxzxyxyzyzxzxy∣=x2+y2+z2xy+yz+zxxz+yx+zy ΣxyΣx2Σxy ΣxyΣxyΣx2=r2u2u2u2r2u2u2u2r2 ∵x2+y2+z2=r2,xy+yz+zx=u2