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Questions  

If z=1+cosθ+isinθsinθ+i(1+cosθ)(0<θ<π/2)

then |z|equals

a
2|sin⁡θ|
b
2|cos⁡θ|
c
1
d
|cot⁡(θ/2)|

detailed solution

Correct option is C

Using z1z2=z1z2 if z2≠0, we get|z|2=(1+cos⁡θ)2+sin2⁡θsin2⁡θ+(1+cos⁡θ)2=1|z|=1

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