If a ∈Z and the equation (x−a)(x−10)+1=0 has integral roots, then the values of a, are
10, 8
12, 10
12, 8
none of these
Since a and x are integers. Therefore,
(x−a)(x−10)+1=0⇒ (x−a)(x−10)=−1
⇒ (x−a=1 and x−10=−1) or, (x−a=−1 and x−10=1)
⇒ (x=9 and a=8) or, (x=11 and a=12)
⇒ a=8 or, a=12