If z=−53+4i5−7i3−4i68+7i5+7i8−7i9 then z is
purely real
purely imaginary
a+ib, where a≠0,b≠0
a+ib, where b=4
z=−53+4i5−7i3−4i68+7i5+7i8−7i9⇒ z¯=−53−4i5+7i3+4i68−7i5−7i8+7i9=−53+4i5−7i3−4i68+7i5+7i8−7i9=z
(Taking transpose)
Hence, z is purely real.