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Questions  

If z=20i-21+20i+21,than one of the possible value of |arg (z)| equals

a
π/4
b
π/2
c
3π/8
d
π

detailed solution

Correct option is A

20i+21 =(5+2i)2  and 20i+21 =(2-5i)2 ∴        z=±(5+2i)±(2+5i) ⇒        z=7(1+i), 3(1-i), 3(-1+i), (-1-i) ⇒      arg(z)= π/4, -π/4, 3π/4, -3π/4      Thus, one of the possible value of |arg(z)| is π/4.

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