First slide
Algebra of complex numbers
Question

If z = (3 + 7i) (a + ib) where a,bZ{0}, is purely imaginary, then the minimum value of |z|2 is

Moderate
Solution

z=(3a7b)+i(3b+7a)

For z to be purely imaginary we have

3a=7ba=7 or b=3            (for least value of |z|)|z|=9+49=58

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