If z=(λ+3)−i5−λ2, then the locus of z is
ellipse
semicircle
parabola
straight line
Let z = x + iy. Then,
x=λ+3 and y=−5−λ2
⇒ (x−3)2=λ2 (1)
and y2=5−λ2 (2)
From Eqs. (1) and (2),
(x−3)2=5−y2 or (x−3)2+y2=5
Obviously it is a semicircle as y < 0. Hence, part of the circle lies below the x-axis.