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Q.

If |Z+2−3i|=5  then locus of Z = x + iy is

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a

x2+y2+x−y=0

b

x2+y2+4x−6y−12=0

c

x2+y2+3x−2y=0

d

3x2+3y2−22x+35=0

answer is B.

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Detailed Solution

|Z+2−3i|=5⇒(x+2)2+(y−3)2=25⇒x2+y2+4x−6y−12=0
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