If A={z:(1+2i)z¯+(1−2i)z+2=0} and B={z:(3+2i)z¯+(3−2i)z+3=0} then
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a
A∩B is a singleton set
b
A⊆B
c
B⊆A
d
A∩B=ϕ
answer is A.
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Detailed Solution
Equations in sets A and B represent straightline with α¯1=1+2i and α¯2=3+2i Since α¯1α1≠α¯2α2 so thelines are intersecting, hence A∩ B is a singleton set.