If z¯=3i+25z+3i then |z| cannot exceed
3
8
16
18
(z¯−3i)(z+3i)=25
⇒ |z−3i|2=25 or |z−3i|=5
Now, |z|=|(z−3i)+3i|≤|z−3i|+|3i|=5+3=8