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Q.

If z¯=3i+25z+3i then |z| cannot exceed

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a

3

b

8

c

16

d

18

answer is B.

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Detailed Solution

(z¯−3i)(z+3i)=25⇒ |z−3i|2=25 or |z−3i|=5Now,           |z|=|(z−3i)+3i|≤|z−3i|+|3i|=5+3=8
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If z¯=3i+25z+3i then |z| cannot exceed