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Questions  

 If |2z42i|=|z|sinπ4argz , then locus of z is/an 

a
ellipse
b
circle
c
parabola
d
pair of straight line

detailed solution

Correct option is A

Let z=x+iy=r(cos⁡θ+isin⁡θ) ,  Then the equation is |2(x−2)+2i(y−1)|=r12cos⁡θ−12sin⁡θ=12(rcos⁡θ−rsin⁡θ)⇒(x−2)2+(y−1)2=12x−y2 It is an ellipse with focus at (2,1) and directrix x−y=0 and eccentricity =12<1 The locus represents an ellipseTherefore, the correct answer is (1).

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