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If zk=coskπ10+isinkπ10 then z1 z2 z3 z4 is equal

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By Expert Faculty of Sri Chaitanya
a
-1
b
2
c
-2
d
1
NEW

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detailed solution

Correct option is A

We have zk=ωk where ω=cos⁡π10+isin⁡π10Thus , z1z2z3z4=ω⋅ω2⋅ω3⋅ω4=ω10=cos⁡10π10+isin⁡10π10                                 [by the De Movire ’s Theorem]=cos⁡π+isin⁡π=−1


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