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Questions  

If z0 lies on the circle |z1|=1and  ω =5/z,then ω lies on

a
a circle
b
an ellipse
c
a straight line
d
a parabola

detailed solution

Correct option is C

z=5/ωand |z−1|=1⇒ 5ω−1=1⇒|ω−5|=|ω|that is, ω lies on the perpendicular bisector of the segment joining 0 and 5+0iTherefore ω lies on the straight line Re⁡(ω)=5/2

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