First slide
Geometry of complex numbers
Question

If z0 lies on the circle |z1|=1and  ω =5/z,then ω lies on

Moderate
Solution

z=5/ωand |z1|=1

 5ω1=1|ω5|=|ω|

that is, ω lies on the perpendicular bisector of the segment joining 0 and 5+0i

Therefore ω lies on the straight line Re(ω)=5/2

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