If z≠0 lies on the circle |z−1|=1and ω =5/z,then ω lies on
a circle
an ellipse
a straight line
a parabola
z=5/ωand |z−1|=1
⇒ 5ω−1=1⇒|ω−5|=|ω|
that is, ω lies on the perpendicular bisector of the segment joining 0 and 5+0i
Therefore ω lies on the straight line Re(ω)=5/2