First slide
Geometry of complex numbers
Question

If z lies on the circle z-1=1 then z-2z equals

Moderate
Solution

Note that z-1=1represents a circle with the segment joining z = 0 and z = 2 +0i as a diameter. 

 If z lies on the circle, then z-2z-0  is purely imaginary. ( since the angle at z is π2)

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