If z=5+t+i25−t2 , (−5≤t≤5) then locus of z is a curve which passes through
5+0i
−2+3i
2+4i
−2−3i
Let z =x +iy so that
x=5+t, y=25−t2
⇒ (x−5)2+y2=25
This clearly passes through 2 + 4i