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If $| z | = 1$ and $w = \frac{z - 1}{z + 1} ($ where $z \neq - 1)$ , then $R e (w)$ equals

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Correct option is A

|z|=1 ⇒zz=1 2Re⁡(w)=w+w¯=z−1z+1+z¯−1z+1=z−1z+1+(1/z)−1(1/z)+1=z−1z+1+1−z1+z=0⇒ Re⁡(w)=0

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If |z|=1 and w=z−1z+1(where z≠−1), then Re(w) equals

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If $| z | = 1$ and $w = \frac{z - 1}{z + 1} ($ where $z \neq - 1)$ , then $R e (w)$ equals