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Questions  

If z=x+iy and x2+y2=16 then the range of ||x||y|| is

a
[0, 4]
b
[0, 2]
c
[2,4]
d
none of these

detailed solution

Correct option is A

Here x=4cos⁡θ,y=4sin⁡θ∴ ∥x|−|y∣∥=|4|cos⁡θ|−4|sin⁡θ||=4||cos⁡θ|−|sin⁡θ||=41−2|cos⁡2θ||sin⁡θ|=41−|sin⁡2θ|Hence, the range is [0, 4].

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