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If $z_{1}$ and $z_{2}$ are the complex roots of the equation ${(x - 3)}^{3} + 1 = 0,$ then $z_{1} + z_{2}$ equals to

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Correct option is D

(x−3)3+1=0 ⇒(x−3−1)3=1⇒x−3−1=1, ω, ω2⇒ x=2, 3−ω, 3−ω2Hence, the sum of complex roots is 6−(ω+ω2) =6--1=7

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If z1 and z2 are the complex roots of the equation (x−3)3+1=0, then z1+z2 equals to

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If $z_{1}$ and $z_{2}$ are the complex roots of the equation ${(x - 3)}^{3} + 1 = 0,$ then $z_{1} + z_{2}$ equals to