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Questions  

If |z|=z+32i,then z equals

 

a
7/6+i
b
-7/6+2i
c
−5/6+2i
d
5/6+2i

detailed solution

Correct option is C

z=|z|−3+2i|z|2=(|z|−3)2+4=|z|2−6|z|+9+4⇒ |z|=13/6Thus, z=−5/6+2i

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