If |z−2||z−3|=2  represents a circle, then its radius is equal to:

Given |z−2||z−3|=2 , let z=x+iy  then ⇒     (x−2)2+y2=2(x−3)2+y2 ⇒        (x−2)2+y2=4[(x−3)2+y2] ⇒     x2+y2+4−4x=4x2+4y2+36−24x ⇒            3x2+3y2−20x+32=0 or         x2+y2−203x+323=0                                   …..(i)we know that, standard equation of circle,         x2+y2+2gx+2fy+c=0                                ……(ii)Comparison of Eq. (i) from Eq. (ii)⇒        2g=−203⇒g=−103,f=0,c=323 Hence, Radius =g2+f2−c=1009−323=49=23