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Q.

If z−4z=2, then the maximum value of zis equal to

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a

1

b

2+2

c

3+1

d

5+1

answer is D.

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Detailed Solution

|z|−4|z|≤||z−4|z|≤z−4z=2⇒                         |z|2−2|z|−4≤0⇒        (|z|−1)2≤5⇒|z|≤1+5.The maximum value 5+1 is attained when z=5+1.
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